College Algebra CLEP Prep Practice Exam

Disable ads (and more) with a membership for a one time $2.99 payment

Prepare for the College Algebra CLEP Test with our comprehensive practice exam. Study with flashcards and multiple choice questions, each offering clues and detailed explanations. Achieve your best score and excel in your exam!

Start Multiple Choice Practice Test
Start Flash Cards

Each practice test/flash card set has 50 randomly selected questions from a bank of over 500. You'll get a new set of questions each time!

Practice this question and more.

What is the root of the quadratic equation 5x^2-14x+9=0?

  1. 3, -1

  2. -1.7, -2.3

  3. -2.5, 1.5

  4. 6, -3

The correct answer is: -1.7, -2.3

The given equation is a quadratic equation in the form of ax^2+bx+c=0, where a=5, b=-14, c=9. To find the roots of a quadratic equation, we can use the quadratic formula x=(-b±√(b^2-4ac))/2a. Plugging in the values we get x=(-(-14)±√((-14)^2-4(5)(9)))/2(5), simplifying we get x=(14±√(196-180))/10, which further gives x=(14±√16)/10, x=(14±4)/10. This gives us two possible solutions, x=3 and x=-1. However, since both options A and D have only one positive value, they cannot be the roots of a quadratic equation. On the other hand, option C

More Questions Like This