College Algebra CLEP Prep Practice Exam

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What is the point-slope form of the equation of the line passing through (-2, 4) and (3, -1)?

  1. y +4 = -1/5 (x + 2)

  2. y - 4 = -1/5 (x + 2)

  3. y -4 = 1/5 (x + 2)

  4. y + 4 = 1/5 (x + 2)

The correct answer is: y +4 = -1/5 (x + 2)

The point-slope form of an equation of a line is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope. In this given question, the points (-2, 4) and (3, -1) are provided. Using these points, we can calculate the slope of the line using the formula m = Δy/Δx = (y2 - y1)/(x2 - x1). Plugging in the values, we get m = (-1 - 4)/(3 - (-2)) = -1/5. Now, we can substitute the value of m and one of the given points (in this case, (-2, 4)) in the point-slope form to get the equation of the line as y - 4 =

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