College Algebra CLEP Prep Practice Exam

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Prepare for the College Algebra CLEP Test with our comprehensive practice exam. Study with flashcards and multiple choice questions, each offering clues and detailed explanations. Achieve your best score and excel in your exam!

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What is the equation of the circle centered at (2,3) with a radius of 5?

(x-2)^2 + (y-3)^2 = 25
(x-2)^2 + (y-3)^2 = 5
(x-2)^2 + (y+3)^2 = 25
(x+2)^2 + (y-3)^2 = 5

The correct answer is: (x-2)^2 + (y-3)^2 = 25

The equation of a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle and r is the radius. In this question, the center of the circle is given as (2,3), so we substitute those values for h and k. The radius of the circle is given as 5, so we substitute that value for r. This gives us (x-2)^2 + (y-3)^2 = 25, which is option A. Option B is incorrect because the radius is squared in the equation, so (x-2)^2 + (y-3)^2 cannot equal 5 for a circle with a radius of 5. Option C is incorrect because the y-coordinate of the center is given as -3 instead of 3, so the equation becomes (x-