College Algebra CLEP Prep Practice Exam

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Prepare for the College Algebra CLEP Test with our comprehensive practice exam. Study with flashcards and multiple choice questions, each offering clues and detailed explanations. Achieve your best score and excel in your exam!

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What is the equation of the circle with the center (-4,7) and the radius 5?

x^2 + y^2 – 10 = 0
(x + 4)^2 + (y – 7)^2 – 25 = 0
(x + 4)^2 + (y – 7)^2 = 5
(x – 4)^2 + (y + 7)^2 = 25

The correct answer is: (x – 4)^2 + (y + 7)^2 = 25

The equation of a circle is given by the equation (x-h)^2+(y-k)^2=r^2, where (h,k) is the center of the circle and r is the radius. In this case, the center is (-4,7) and the radius is 5, so the correct equation would be (x+4)^2 + (y-7)^2 = 5^2, which simplifies to (x-4)^2 + (y+7)^2 = 25. Option A is incorrect because the radius is not squared. Option B is incorrect because the equation should only contain the squared terms of (x-h) and (y-k), not additional constant terms. Option C is incorrect because the radius should be squared in the equation. Therefore, the correct answer is D.