College Algebra CLEP Prep Practice Exam

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Prepare for the College Algebra CLEP Test with our comprehensive practice exam. Study with flashcards and multiple choice questions, each offering clues and detailed explanations. Achieve your best score and excel in your exam!

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What is the equation of the circle with the center (3,7) and the radius 4?

(x-3)2 + (y-7)2 = 4
(x+3)2 + (y+7)2 = 16
(x-3)2 + (y+7)2 = 16
(x+3)2 + (y-7)2 = 16

The correct answer is: (x-3)2 + (y+7)2 = 16

The equation for a circle is (x-a)^2 + (y-b)^2 = r^2, where (a,b) is the center and r is the radius. Therefore, the equation for the circle with center (3,7) and radius 4 should be (x-3)^2 + (y-7)^2 = 16. This eliminates options A, B, and D as they have the incorrect values for a and b. Option B has the incorrect value for r as well. This leaves option C as the only correct answer.