College Algebra CLEP Prep Practice Exam

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Prepare for the College Algebra CLEP Test with our comprehensive practice exam. Study with flashcards and multiple choice questions, each offering clues and detailed explanations. Achieve your best score and excel in your exam!

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What is the equation of the circle with diameter from (-3,2) to (11,4)?

(x + 7)^2 + (y - 3)^2 = 25
(x - 4)^2 + (y + 1)^2 = 25
(x + 4)^2 + (y - 1)^2 = 25
(x - 7)^2 + (y + 3)^2 = 25

The correct answer is: (x - 4)^2 + (y + 1)^2 = 25

The equation of a circle with center (h,k) and radius r is (x-h)^2 + (y-k)^2 = r^2. For this problem, we need to find the center of the circle, which is the midpoint of the diameter connecting (-3,2) and (11,4). Using the midpoint formula, we get the center as (4, 1). And since the circle has a diameter of 10 units, the radius is 5. Plugging these values into the equation for a circle, we get (x-4)^2 + (y-1)^2 = 25, which is equivalent to option B. Option A has the wrong center and radius, as (x+7)^2 + (y-3)^2 = 25 would result in a circle with center (-7, 3) and radius 5