College Algebra CLEP Prep Practice Exam

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Prepare for the College Algebra CLEP Test with our comprehensive practice exam. Study with flashcards and multiple choice questions, each offering clues and detailed explanations. Achieve your best score and excel in your exam!

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The equation of the circle that is centered at (2,3) and has the radius of 8 is

(x - 2)2 + (y - 3)2 = 2
(x + 2)2 + (y - 3)2 = 8
(x-2)2 + (y-3)2 = 64
(x + 2)2 + (y + 3)2 = 8

The correct answer is: (x-2)2 + (y-3)2 = 64

The equation of a circle is usually written in the form (x - h)^2 + (y - k)^2 = r^2, where (h, k) represents the center of the circle and r represents the radius. In this question, the center is (2,3) and the radius is 8. So the correct equation should be (x-2)^2 + (y-3)^2 = 8^2 = 64. Option A has incorrect coefficients for both (x-2)^2 and (y-3)^2, and option B has an incorrect coefficient for (x+2)^2. Option D has incorrect coefficients for both (x+2)^2 and (y+3)^2. Therefore, the correct answer is option C with the correct coefficients for both (x-2)^2 and (y-3)^2